duanjin9035 2011-08-31 16:31
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Php图像验证

Thus anyone has any idea why this code is not working for me

$type1 = $_FILES['textfield2']['type'];
$type2 = $_FILES['textfield3']['type']; 

if($type1 == 'image/gif' || $type1 == 'image/png' && $type2 == 'image/gif' || $type2  == 'image/png')
{
    echo 'Valid';
    echo $type1.'<br />'.$type2;
}
else
{
    echo 'Invalid';
}

If i select 1st file as a zip or any other format and then next as png it is going to valid that what i should not

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  • dongxing9219 2011-08-31 16:34
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    PHP's operator precedence makes && bind tighter than ||, so your test is coming out as:

    if($type1 == 'image/gif' || ($type1 == 'image/png' && $type2 == 'image/gif') || $type2  == 'image/png')
                                ^----------------------------------------------^
    

    Beyond that, do not use the user-provided ['type'] data for this. It's utterly trivial to forge, and someone can set to 'image/gif' while uploading nastyvirus.exe.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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