如果出现错误声明，则更容易在php中的文本字段中保留数据

Question

I have a simple xhtml form with textboxes asking the user for their name, id, address etc. I have to use php to validate the data. For example in the ID field exactly 6 numerical values are allowed, if thats not the case, it shows an error to the user asking them to fix it. What i want do is, when the user clicks submit with the incorrect data, i want to keep the data in the field when the error shows up. I am currently doing that by:-

 <td><label for="customerid">*Customer ID: </label></td>
    <td><input type="text" value="
<?php if(($_POST['customerid'] != $id) || ($_POST["customerfname"] != $fname) 
||    ($_POST["customerlname"] != $lname)){echo $_POST['customerid'];} ?>"

id="customerid" name="customerid"/>

I have just been modyifying that statement for all textboxes but as you can imagine it will get a little complicated if i have to do that for 10 boxes. i was wondering if it was an easier way to do this.

bold UPDATED

<td> <select name="state" id="state"  value="<?php echo (isset($_POST["state"]) ?  : ''); ?>"> 
    <option value="--">--</option>
    <option value="ACT">ACT</option>
    <option value="NSW">NSW</option>
    <option value="NT">NT</option>
    <option value="QLD">QLD</option>
    <option value="SA">SA</option>
 </select>
</td>

Answer 1

Something like this?

<input type="text" name="customerid" value="<?php echo (isset($_POST['customerid']) ? $_POST['customerid'] : ''); ?>">

Update - run your checks before the form is re-generated

<?php

if(($_POST['customerid'] != $id) || ($_POST["customerfname"] != $fname) || ($_POST["customerlname"] != $lname))
{
    // do nothing
}
else
{
    $_POST['customerid'] = '';
}

?>

<input type="text" name="customerid" value="<?php echo (isset($_POST['customerid']) ? $_POST['customerid'] : ''); ?>">