douxun2023 2018-07-06 08:18
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SQL查询无法工作无法弄清楚为什么[关闭]

In a timetracking application I'm developing right now this query fails and I can't figure out why. The Var $userID has the value 1 in it what is right. The naming of each table and field should be correct because I checked it like four times.

query:

$query= 'SELECT arbeiter.id AS id,'.                                
        'tblMitarbeiterUUID.dtLastname AS dtLastname, ' .
        'tblMitarbeiterUUID.dtFirstname AS dtFirstname, ' .
        'FROM arbeiter, tblMitarbeiterUUID ' .
        'WHERE ' .
        'arbeiter.id =' . $userID .' ' .
        'AND arbeiter.start_date < NOW() '.                                         
        'AND (arbeiter.end_date=\"0000-00-00 00:00:00\" '.
        'OR arbeiter.end_date > NOW())';

If I echo the Query I get this:

SELECT arbeiter.id AS id,tblMitarbeiterUUID.dtLastname AS dtLastname, tblMitarbeiterUUID.dtFirstname AS dtFirstname, FROM arbeiter, tblMitarbeiterUUID WHERE arbeiter.id =1 AND arbeiter.start_date < NOW() AND (arbeiter.end_date=\"0000-00-00 00:00:00\" OR arbeiter.end_date > NOW())

The error I get when trying to paste query directly into my sql tool:

SQL syntax error near :"FROM arbeiter, tblMitarbeiterUUID WHERE arbeiter.id =1 AND arbeiter.start_date <"

I bet it should be an easy fix for one of you guys. Or is my approach to this wrong and should I try it with an INNER JOIN ?

Thanks in advance

ERRORS found the comma after dtFirstname and the backslashes to escape the " were the problems! Now everything works fine.

  • 写回答

1条回答 默认 最新

  • duanlang0025 2018-07-06 08:19
    关注

    You got a little syntax error with redundant comma , at the end.

    'tblMitarbeiterUUID.dtFirstname AS dtFirstname, ' 
    

    Change it to:

    'tblMitarbeiterUUID.dtFirstname AS dtFirstname' 
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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