dougua9328 2016-02-17 10:30
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Laravel Blade如何使用@show动作打印出uri

In my view, I want to print a controller uri like this ShopController@show.

set the var $controller = 'ShopControll';

in the view:

action($controller.'@show',$id)

but there are some error occured:

ErrorException in UrlGenerator.php line 603:
Action App\Http\Controllers\ShopController<?php echo $__env->yieldSection(); ?> not defined. 

if like this:

action('ShopController@show',$id)

it works, output is:

http://example.com/show/1

So, what's the difference?

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2条回答 默认 最新

  • douqi4673 2016-02-17 10:43
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    @show is a blade directive, blade parse it you want to show this as section please check here example

    @section('sidebar')
                This is the master sidebar.
    @show
    

    https://laravel.com/docs/5.2/blade#template-inheritance

    you can modify you method like this

    action($controller,'show',$id)
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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