PHP：获取脚本的参数数量

Question

I cannot find (aka: don't have time to read all the manuals) a way to get the number of arguments passed to a php script. I have a fixed argument, "id" and, after that, nothing or a list of dynamic arguments. I actually handle the case of a not empty list but I cannot check if the list (after "id") is empty because the arguments are dynamic so, unknown.

first case, handled:

php_script.php?id=123&aaa=xxx&bbb=yyy

second case, not handled:

php_script.php?id=456

Is there a way ?

I tried $argv and $argc but I get an error.

Notice: Undefined variable: argv in...

Answer 1

Use count

$arg_num = count($_GET);