如何从ajax成功函数中显示图像？

Question

I have created ajax function like this...In this I will get the value from run time and i need to return the photo according to that value..In success function i need to display that image in particulat div

var num=document.getElementById('number').value;
$.ajax({
    url:"image.php?val="+num,
    contentType: "image/png",
    success:function(img)
    {
        $('#image').html('<img src="data:image/png;base64,' + img + '" />');
    }
    });

image.php page

$sql_sub = select_query("select pic from  photo  where picnum=".$_GET['val']."");
$img = $sql_sub[0][0]->load();
header("Content-type: image/png");
ob_start();
imagepng($img);
echo "data:image/png;base64,", base64_encode(ob_get_clean());

Answer 1

var num=document.getElementById('number').value;
$.ajax({
url:"image.php?val="+num,
 type: "POST",
 dataType: "html",
success:function(img)
{
    $('#image').html('<img src="data:image/png;base64,' + img  + '" />');
}
});

image.php

$sql_sub = select_query("select pic from photo where picnum=".$_GET['val']."");
$img = $sql_sub[0][0]->load();
header("Content-type: image/png");
ob_start();
echo $img;
echo "data:image/png;base64,", base64_encode(ob_get_clean());