duanlie7962 2012-06-06 10:51
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mysql_result()期望参数1是资源,布尔给定[重复]

Possible Duplicate:
Warning: mysql_fetch_array() expects parameter 1 to be resource, boolean given in

I think the title says everything.

Here's my code:

function user_count(){
    $query = "SELECT COUNT * FROM  users  WHERE  active = 1";
    $result = mysql_query($query);
    return mysql_result($result, 0);
}

With this function. I'm trying to get all the users from the database who are "active"... All is OK with db connection and that stuff.

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3条回答 默认 最新

  • dongtan7351 2012-06-06 11:30
    关注
    function user_count(){
        $query = "SELECT COUNT(user_id) FROM  `users` WHERE  `active` = 1";
        $result = mysql_query($query) or die($query."<br/><br/>".mysql_error());
        return mysql_result($result, 0);
    }
    

    This works.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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