//get the current member count
$sql = ("SELECT count(member_id) as total_members from exp_members");
$result = mysql_query($sql) or die(mysql_error());
$num_rows = mysql_num_rows($result);
if ($num_rows != 0) {
while($row = mysql_fetch_array($result)) {
$total_members = $row['total_members'];
}
}
//get list of products
$sql = ("SELECT m_field_id, m_field_label from exp_member_fields where m_field_name like 'cf_member_ap_%' order by m_field_id asc");
$result = mysql_query($sql) or die(mysql_error());
$num_rows = mysql_num_rows($result);
if ($num_rows != 0) {
while($row = mysql_fetch_array($result)) {
$m_field_id = $row['m_field_id'];
$m_field_label = $row['m_field_label'];
$sql2 = ("SELECT count(m_field_id_".$m_field_id.") as count from exp_member_data where m_field_id_".$m_field_id." = 'y'");
$result2 = mysql_query($sql2) or die(mysql_error());
$num_rows2 = mysql_num_rows($result2);
if ($num_rows2 != 0) {
while($row2 = mysql_fetch_array($result2)) {
$p = ($row2['count']/$total_members)*100;
$n = $row2['count'];
$out .= '<tr><td>'.$m_field_label.'</td><td>'.number_format($p,1).'%</td><td>'.$n.'</td></tr>';
}
}
}
}
如何使这个MySQL Count查询更有效?
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3条回答 默认 最新
- dongqiuge5435 2011-05-19 00:40关注
count query would always return 1 row, so you don't need the loop
$sql = ("SELECT count(member_id) as total_members from exp_members"); $result = mysql_query($sql) or die(mysql_error()); $row = mysql_fetch_array($result); $total_members = $row['total_members'];
Other than that i am not sure how you can make it better. You can do the same for both of your count queries.
As these are straight forward queries, any bottleneck i guess now would be on the MySQL end
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