使用array_pop后返回已删除的项目

Question

This is my array:

$my_array = array("1", "2", "3", "4", "5");

How can I return the deleted item after using shuffle($my_array) and array_pop($my_array)?

I want something like: The deleted number is: 3.

This is my code:

$my_array = array("1", "2", "3", "4", "5");
shuffle($my_array)
array_pop($my_array)

How can I achieve this?

Answer 1

According to the PHP documentation, array_pop() will return the value that was deleted:

Return Values

Returns the value of the last element of array. If array is empty (or is not an array), NULL will be returned.

So, you can simply do:

$my_array = array(1, 2, 3, 4, 5);
shuffle($my_array);
echo 'The deleted number is: <b>'.array_pop($my_array).'</b>';