douxi3977
2017-04-12 08:11
浏览 647
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未捕获的SyntaxError:在位置0的JSON中出现意外的令牌:在对象的JSON.parse(<anonymous>)处。<anonymous>

i have an error in JSON.parse(), i have .php file which contain method to retrieve data from database and .js file for autoComplete function, my .php file return data as string and i need to convert it to object by using JSON.parse().

this is my php file

<?php 
include_once("database_conn.php");

function request($conn)
{
    $eventstArray = array();

    $events = "SELECT * 
                FROM te_events,te_category,te_venue
                WHERE te_events.venueID = te_venue.venueID 
                    AND te_events.catID = te_category_catID
                ORDER BY 1
                ";

    $eventsQuery1 = mysqli_query($conn,$events) or DIE (mysqli_error($conn));

    while($eventsQuery2 = mysqli_fetch_array($eventsQuery1))
    {
        $eventstArray[] = array
        (
            'label'         => $eventsQuery2['eventTitle'];
            'venue'         => $eventsQuery2['venueName'];
            'category'      => $eventsQuery2['catDesc'];
            'price'         => $eventsQuery2['eventPrice'];
            'description'   => $eventsQuery2['eventDescription'];
        );
    }

    return json_encode($eventstArray);
}
echo request($conn);
?>

and this is my autoComplete.js file

$(document).ready(function()
            {
                'use strict';
                $.ajax
                ({
                    method: "get",
                    url: "requestOffer.php"
                })
                .done(function(data)
                {
                    var offers = JSON.parse(data);

                    // now we have the data attach the autocomplete
                    $('#EOffers').autocomplete
                    ({
                        minLength:3,
                        source: offers,
                        select: function(event, ui) 
                        {
                            $('#chosenEvent').text(ui.item.label);
                            $('#chosenEvent').text(ui.item.vanue);
                        }
                    });
                });
            });

i can't remove the JSON.parse() because i need that to convert from string to object, hope someone can help me to solve this and i really appreciate that.

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5条回答 默认 最新

  • dqv84329 2017-04-12 08:20
    已采纳

    The error is within your server side, when there's an error on your server side, the response comes with html tags '<' when there's an error php will add tag with the error message. Therefore your json contains the html tags and becomes invalid because of unexpected tags.

    The error is within this array

    $eventstArray[] = array
            (
                'label'         => $eventsQuery2['eventTitle'];
                'venue'         => $eventsQuery2['venueName'];
                'category'      => $eventsQuery2['catDesc'];
                'price'         => $eventsQuery2['eventPrice'];
                'description'   => $eventsQuery2['eventDescription'];
            );
    

    it should be

    $eventstArray[] = array(
                'label' => $eventsQuery2['eventTitle'],
                'venue' => $eventsQuery2['venueName'],
                'category' => $eventsQuery2['catDesc'],
                'price' => $eventsQuery2['eventPrice'],
                'description' => $eventsQuery2['eventDescription']
            );
    

    (The problem source was the semi-colon(;) after the description value. It should be only at the end of array)

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  • dongxibo2095 2017-04-12 08:24

    That error is normally seen when the value given to JSON.parse is actually undefined. So, I would check the code that is trying to parse this - most likely you are not parsing the actual string shown here.

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  • douyong6589 2017-04-12 08:31

    It's server side error. You can check the value returned from server(php code) using browser's developer tools like firefox and check the response message.

    In addition, maybe you can remove JSON.parse() and add dataType: "json" inside the ajax function

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  • dongtiao0657 2019-04-19 11:43

    Check if only the json encoded response is being thrown back only. If you do things like var dump in the php script make sure you comment it out as it also get attached to your javascript response

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  • doutan1637 2019-06-05 08:18

    Check this option if you are sure that your php code is correct but the returned json string cannot be parsed.

    I had a similar problem. What I found was that my PHP code had been saved as UTF8 but without the No-BOM option. That added three extra chars: ο»Ώ (hex: EF BB BF) at the beginning of the file causing the returned json string to have those extra chars at the beginning.

    here is how the beginning of my php file: ο»Ώ < ?php include...

    preview of code in hex mode

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