douyue8364
douyue8364
2019-07-02 21:33

PHP生成具有多个数组的JSON

已采纳

i want to generate json in this format

{
    "name": "item1",
    "description": "mydescript1"

}, 
{
    "name": "item2",
    "description": "mydescript2"

}

i have done this so far

for ($i = 0; $i<sizeof($name_); $i++){
    $ToSend_Json["name"]  = $name_[$i];
    $ToSend_Json["description"]  = $description_[$i];


}
 echo (json_encode($ToSend_Json));

the output i get for this is the last json which in this case is

 {
    "name": "item2",
    "description": "mydescript2"

}

what will be the correct way to do this

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1条回答

  • dongwu3747 dongwu3747 2年前

    You're overwriting the values at each iteration of the loop. You should use an array for each iteration.

    $json_array = [];
    
    for ($i = 0; $i < count($name_); $i++){
        $ToSend_Json["name"] = $name_[$i];
        $ToSend_Json["description"] = $description_[$i];
        $json_array[] = $ToSend_Json;
    }
    
    echo json_encode($json_array);
    

    Alternatively, you could use a foreach which is a better method for iterating a loop:

    $json_array = [];
    
    foreach ($name_ as $i => $name) {
        $ToSend_Json["name"] = $name;
        $ToSend_Json["description"] = $description_[$i];
        $json_array[] = $ToSend_Json;
    }
    
    echo json_encode($json_array);
    
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