dqwh1201
dqwh1201
2016-12-07 10:48
浏览 37
已采纳

语法错误,意外'$ type'(T_VARIABLE),期待'('[重复]

This question already has an answer here:

  if($_POST) {
  $type = $_POST['roll'];
  if $type == 1 {
    $number = rand(1,100)
    if $number <= 50 {
      echo "Winner!"
    }
    else {
      echo "Loser!"
    }
  }
};

Can't figure out what is wrong. I am kinda new to PHP also. Type (or roll) is always 1 (for now)

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1条回答 默认 最新

  • dsutuyxe088689
    dsutuyxe088689 2016-12-07 10:51
    已采纳

    I think you just need to put

    if ($type == 1) {
    

    instead of your actual statement, the condition of the if need that. And so you'll need it too on the second "if"

    Watch what your error is showing, it's exactly what you need.

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