使用x索引循环PHP数组，但总是返回3个结果

Question

I have an array with a random number of words. It can contain a single word as a minimum or more than 10 words. Example:

$words = array (
 0 => 'This',
 1 => 'is',
 2 => 'my',
 3 => 'word'
)

Now, lets say i want to echo out 6 words from this array, starting over when we reach the end of the array. I want the logic to be something like this

for ($i=0; $i < 6 ; $i++) { 
    //if $words[$i] exist, print it, else reset the array and start over until we reach all 6
}

I'd like the result to be: "This is my word this is"

I struggle to figure out the maths for this. Any help would be much appreciated!

Thanks

Answer 1

To handle if $words[$i] exist, print it, else reset the array I'd use something neater $i % count($array), for example.

$array = array(
    '0' => 'This',
    '1' => 'is',
    '2' => 'my',
    '3' => 'word'
);

for ($i = 0; $i < 6; $i++) {
    echo $array[$i % count($array)] . ' ';
}

// "This is my word This is "

Or if you wanted your exact output as specified in your question, (no spaces on the end), I'd probably do

$string = '';
for ($i = 0; $i < 6; $i++) {
    $string .= $array[$i % count($array)] . ' ';
}

echo trim($string);

// "This is my word This is"

or alternatively something like

echo $array[$i % count($array)] . ($i == 5 ? null : ' ');

// "This is my word This is"