douyingmou1389 2011-07-12 17:28
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将图像从URL转换为真实图像以保存在服务器上。 (PHP)

header('Content-Type: image/jpeg');
$imageURL = $_POST['url'];
$image = @ImageCreateFromString(@file_get_contents($imageURL));

if (is_resource($image) === true)
    imagejpeg($image, 'NameYouWantGoesHere.jpg');

else
    echo "This image ain't quite cuttin it.";

This is the code I have to convert a url that I receive from an html form into an image. However, whenever I try to display it or take it off the server to look at it, it 'cannot be read' or is 'corrupted'. So for some reason it is converted to an image, recognized as a proper resource, but is not proper image at that point. Any ideas?

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  • douliao5550 2011-07-12 17:32
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    You don't want ImageCreateFromString - using file_get_contents is getting you the actual binary data for the image.

    Try $image = @imagecreatefromjpeg(@file_get_contents($imageURL)); and see if you like the results better (assuming the original is a JPEG).

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