douchu5131 2014-05-02 13:21
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添加MySQL查询的链接[关闭]

Hi I'm new to PHP & MySQL and I am trying to write a journal page for an assignment, but I am not sure how to link a query to another page that shows the full query that has been clicked. Basically so the user can access their previous journal entries. below is the code I have written so far:

<?php
session_start();
if(isset($_SESSION['uname'])){
echo "Welcome " . $_SESSION['uname'];
}
require_once 'PHP/Constants.php';
$conn = new MySQLi(DB_SERVER, DB_USER, DB_PASSWORD,DB_NAME) or die ('There was a problem connecting to the database');
$uname = $_SESSION['uname'];
$query="SELECT Username, Date_Created, Title FROM journal";
$result=mysqli_query($conn, $query);
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>My Journal</title>
</head>

<body>
<p>
<h1>My Journal</h1>
</p>
    <?php
        echo "<table width='400' border='1' cellspacing='0' cellpadding='3'>
            <tr>
            <th>Date</th>
            <th>Title</th>
            </tr>";
            while ($rows=mysqli_fetch_array($result)){
                if($rows['Username']=$uname) {
                    echo "<tr>";
                    echo "<td>" . $rows['Date_Created'] . "</td>";
                    echo "<td>" . $rows['Title'] . "</td>";
                    echo "</tr>"; 
                } else echo "No Journal Entries Found";
            }
        echo "</table>";
    ?>
    </table>    
<form method="post" action="new_entry.php">
    <p>
        <input type="submit" id="new_entry" value="New Entry" name="new_entry" />
    </p>
</form>
<form method="post" action="choices.php">
    <p>
        <input type="submit" id="back" value="Back" name="back" />
    </p>
</form>
</body>
</html>

Thank you in advance for any help - Nick

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1条回答 默认 最新

  • doufei4418 2014-05-02 13:52
    关注

    First of all you have to have an ID or an unique column in your table, in this case let's say that UserName is unique. So you print your link to another php file and send that parameter by GET:

    while ($rows=mysqli_fetch_array($result)){
    if($rows['Username']==$uname) {
        echo "<tr>";
        echo "<td>" . $rows['Date_Created'] . "</td>";
        echo "<td>" . $rows['Title'] . "</td>";
        echo "<td><a href='info.php?username=".$rows['Username']."'>Link</a></td>";
        echo "</tr>"; 
    } else 
         echo "No Journal Entries Found";
    }
}

    Now in info.php, you recive the value and query the database using the given username:

    <?php
$username = $_GET['username'];
// Escape value to prevent SQL injection
...
$query="SELECT * FROM journal WHERE UserName = '".$username."'";
// And then display the info as you want
...

    Hope this help you.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

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