duanhuizhe6767 2013-02-11 21:18
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PHP IF其他声明不起作用[关闭]

I'm having problems with my IF statement. Why does my code just always say that a is NOT greater than b what have I done wrong? Even when the number is greater it just says it's not?

<?php
//vars
$A = '454';
$B = '1001';
?>


<?php
function difference($val3, $val4)
{
    $subtract = ($val3 - $val4);
    return $subtract;
}

// random number generator function
function random($min, $max) 
{
  return rand($min,$max);
}


$ANum = random(1,$A);
$BNum = random(1,$B);
$difference = "-170"; //difference($teamANum, $teamBNum);


function result()
{
    if ($ANum > $BNum) 
        {
            echo "a is greater than b";
        } 
    else 
        {
             echo "a is NOT greater than b";
        }

}

?>

<?php
echo "A: ".$teamANum."
";
echo "B: ".$teamBNum."
";
echo "Difference: ".$difference."
";
echo result()."
";
?>

Thanks

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3条回答 默认 最新

  • douyinghuo8874 2013-02-11 21:21
    关注

    You are out of scope.

    function result($ANum, $BNum)
    {
    
        if ($ANum > $BNum) 
            {
                echo "a is greater than b";
            } 
        else 
            {
                 echo "a is NOT greater than b";
            }
    
    }
    

    Pass the variables as parameters to the function.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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