dro44817 2013-07-04 06:19
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UPDATE .. SET .. WHERE SQL查询失败[关闭]

I am trying to sort out a query on a web app that I'm making, which keeps failing and I have no idea why! The code is below:

$update = $_GET['update'];
if($update == "true"){
    $setDetails="UPDATE users SET email='{$_POST['email']}', api_key='{$_POST['api_key']}', api_secret='{$_POST['api_secret']}' WHERE username={$_POST['username']}";
    if(mysql_query($setDetails)){
        $updatemsg = '<div class="alert alert-success"><a href="#" class="close" data-dismiss="alert">×</a><strong>Success!</strong> Your details have been updated in our database.</div>';
    }else{
        $updatemsg = '<div class="alert alert-error"><a href="#" class="close" data-dismiss="alert">×</a><strong>Failure!</strong> Your details could not be updated in our database. Please try again later or contact us if this keeps happening.</div>';
    }
}else if($update == "false"){
    $updatemsg = '<div class="alert alert-success"><a href="#" class="close" data-dismiss="alert">×</a><strong>Success!</strong> Your changed were discarded.</div>';
}

Any idea's, help or tips? Note that further down my web app I have SELECT * FROM users WHERE username='$username' which works fine so there is no issue with the database connection.

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2条回答 默认 最新

  • douwen7331 2013-07-04 06:22
    关注
    $update = $_GET['update'];
    if($update == "true"){
        $setDetails="UPDATE users SET email='{$_POST['email']}', api_key='{$_POST['api_key']}', api_secret='{$_POST['api_secret']}' WHERE username='{$_POST['username']}'";
        if(mysql_query($setDetails)){
            $updatemsg = '<div class="alert alert-success"><a href="#" class="close" data-dismiss="alert">×</a><strong>Success!</strong> Your details have been updated in our database.</div>';
        }else{
            $updatemsg = '<div class="alert alert-error"><a href="#" class="close" data-dismiss="alert">×</a><strong>Failure!</strong> Your details could not be updated in our database. Please try again later or contact us if this keeps happening.</div>';
        }
    }else if($update == "false"){
        $updatemsg = '<div class="alert alert-success"><a href="#" class="close" data-dismiss="alert">×</a><strong>Success!</strong> Your changed were discarded.</div>';
    }
    

    Details: Your code:

    $setDetails="UPDATE users SET email='{$_POST['email']}', api_key='{$_POST['api_key']}', api_secret='{$_POST['api_secret']}' WHERE username={$_POST['username']}";
    

    Correct Code:

     $setDetails="UPDATE users SET email='{$_POST['email']}', api_key='{$_POST['api_key']}', api_secret='{$_POST['api_secret']}' WHERE username='{$_POST['username']}'";
    

    Missing ' around username string.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论
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