doushang9172 2012-12-23 16:20
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来自匿名函数的PHP访问变量[重复]

Possible Duplicate:
Render a variable during creation of anonymous PHP function

I am still quite new with PHP and this bothers me:

class Controller {
    ...
    ...
    function _activateCar() {
        $car_id = $this->data['car']->getId();
        // $car_id == 1
        $active_car = array_filter($this->data['cars'], function($car){
            // $car_id undefined
            return $car->getId() == $car_id;
        });
    }
    ...
    ...
}

Why can't the function inside array_filter access the $car_id variable? Keeps saying undefined.

Is there an other way to make $car_id accessible than to make a $_GET['car_id'] = $car_id;? Using the global keyword didn't help.

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2条回答 默认 最新

  • douzong3599 2012-12-23 16:22
    关注

    You need to add use($car_id) to your anonymous function, like so:

    $active_car = array_filter($this->data['cars'], function($car) use($car_id){
        // $car_id undefined
        return $car->getId() == $car_id;
    });
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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