I have a database in which there are NOT NULL
and NULL
fields (the NULL
s are of the VARCHAR
type).
When I try to enter data in the NULL
fields via my query, it does not insert them.
The data isn't entered all at the same time:
- with a form I insert the data in the
NOT NULL
fields - with another form insert the data in the
NULL
fields.
Why doesn't the query for entering data in the NULL
fields sork?
I tried to find an answer to similar questions, but they don't work or are not suitable for my problem:
FIRST FORM register.php
<?php
if($_SERVER['REQUEST_METHOD']=='POST'){
// echo $_SERVER["DOCUMENT_ROOT"]; // /home1/demonuts/public_html
//including the database connection file
include_once("config.php");
$id_akR = $_POST['id_akR'];
$numero_telefonoR = $_POST['numero_telefonoR'];
if($id_akR == '' || $numero_telefonoR == '' ){
echo json_encode(array( "status" => "false","message" => "Parameter missing!") );
}else{
$query= "SELECT * FROM RistoratoreAK WHERE id_akR='$id_akR' OR numero_telefonoR ='$numero_telefonoR' ";
$result= mysqli_query($con, $query);
$query2 = "SELECT ak_id, numero_telefono FROM AccountKit WHERE ak_id = '$id_akR' OR numero_telefono = '$numero_telefonoR'";
$result2= mysqli_query($con, $query2);
if(mysqli_num_rows($result) > 0){
echo json_encode(array( "status" => "false","message" => "User already exist in Ristoratore!") );
}else if(mysqli_num_rows($result2) > 0) {
echo json_encode(array( "status" => "false","message" => "User already exist in Cliente!") );
}else{
$query = "INSERT INTO RistoratoreAK (id_akR, numero_telefonoR) VALUES ('$id_akR','$numero_telefonoR')";
if(mysqli_query($con,$query)){
$query= "SELECT * FROM RistoratoreAK WHERE numero_telefonoR ='$numero_telefonoR'";
$result= mysqli_query($con, $query);
$emparray = array();
if(mysqli_num_rows($result) > 0){
while ($row = mysqli_fetch_assoc($result)) {
$emparray[] = $row;
}
}
echo json_encode(array( "status" => "true","message" => "Successfully registered!" , "data" => $emparray) );
}else{
echo json_encode(array( "status" => "false","message" => "Error occured, please try again!") );
}
}
mysqli_close($con);
}
} else{
echo json_encode(array( "status" => "false","message" => "Error occured, please try again!") );
}
?>
SECOND FORM register2.php
<?php
if($_SERVER['REQUEST_METHOD']=='POST'){
include 'config2R.php';
$con = mysqli_connect($HostName,$HostUser,$HostPass,$DatabaseName);
$nome = $_POST['nomeR'];
$cognome = $_POST['cognomeR'];
$data_nascita = $_POST['data_nascitaR'];
$sesso = $_POST['sessoR'];
$nome_ristorante = $_POST['nome_ristoranteR'];
$CheckSQL = "SELECT nome_ristorante FROM RistoratoreAK WHERE nome_ristorante='$nome_ristorante'";
$check = mysqli_fetch_array(mysqli_query($con,$CheckSQL));
if(isset($check)){
echo 'Ristorante già registrato';
}
else{
$Sql_Query = "INSERT INTO RistoratoreAK (nomeR,cognomeR,data_nascitaR,sessoR,nome_ristorante) values ('$nome','$cognome','$data_nascita','$sesso','$nome_ristorante')";
if(mysqli_query($con,$Sql_Query))
{
echo 'Registration Successfully';
}
else
{
echo 'Something went wrong';
}
}
}
mysqli_close($con);
?>
My DB contains a table called "RistoratoreAK", the fields are :
id INT PrimaryKey
id_ak VARCHAR NOT NULL
number VARCHAR NOT NULL
nomeR VARCHAR NULL
cognomeR VARCHAR NULL
sessoR VARCHAR NULL
data_nascitaR VARCHAR NULL
nome_ristorante VARCHAR NULL
note: Excuse me if the code isn't secure (I didn't use PDO), this code is just a test to learn how to upload data to the database.