将变量从html输入传递到包含的php文件

Question

I have situation where I have an accordian and I am referencing a php file gridlist.php within another php file displayvar.php. In other words the context of displayvar.php are shown in the webpage gridlist.php. Now gridlist.php has a checkbox input:

 <input type="checkbox" id="foodlike" value="icecrm">I like ice cream</input>
 <input type="checkbox" id="foodlike" value="pizza">I like pizza</input>
 <input type="checkbox" id="foodlike" value="soda">I like soda</input>

Now when I check on the checkboxes in the table referenced by gridlist.php displayvar.php should be able to display a list of the items checked. For instance it should display if all three checkboxes are checked:

 icecrmpizzasoda

If the last one is checked then only soda should be displayed. Keep in mind because this displayvar.php is displayed within the context of the website gridlist.php I used the following command in gridlist.php:

<?php include 'displayvar.php'; ?>

I tried in the displayvar.php to obtained the variables foodlike (as defined by the variable id in the checkbox gridlist.php) from gridlist.php and then echo them based on this snippet of code:

<?php

   $like=$_POST['foodlike'];
   echo "$like";

?>

How can I tweak this code to get my desired result?

Answer 1

You can achieve this with :

gridlist.php

<form method="post" action="displayvar.php">
    <input type="checkbox" name="icecrm" value="icecrm">I like ice cream</input>
    <input type="checkbox" name="pizza" value="pizza">I like pizza</input>
    <input type="checkbox" name="soda" value="soda">I like soda</input>
    <input type="submit" value="Submit">
</form>

displayvar.php

<?php
    $icecrm = isset($_POST['icecrm']) ? $_POST['icecrm'] : null;
    $pizza = isset($_POST['pizza']) ? $_POST['pizza'] : null;
    $soda = isset($_POST['soda']) ? $_POST['soda'] : null;

    echo is_null($soda) ? $icecrm.$pizza : $soda;
?>