PHP：如何遍历目录并排除数组中出现的任何内容

Question

I have a code that lists all of the files and folders in a directory. What I can't figure out is how to exclude certain files based on a list of values in an array. For instance, I have an array like the one below. I want to reference this list and exclude any item that contains one of those substrings:

$hideDir = array('.php', '.html', '.css');

Here's my current loop. Any thoughts on what I'm doing wrong?

echo '<ul>';
foreach($hideDir as $v) {
if ($handle = opendir('.')) {
    while (false !== ($entry = readdir($handle))) { 
        if (strpos($entry, $v) > -1) {
            //do nothing
        }else{
            echo '<li>' . "$entry" . '</li>' . "
";
        }
    }
}
closedir($handle);
}
echo '</ul>';

Answer 1

You're close, but you should drop the whole foreach. Just check while reading the dir, whether the current entry's extension (that can be checked with pathinfo()) is in the array, using in_array():

echo '<ul>';
if ($handle = opendir('.')) {
    while (false !== ($entry = readdir($handle))) {
        // Get entry info
        $entryInfo = pathinfo(__DIR__ . DIRECTORY_SEPARATOR . $entry);

        // Is this a "hidden" extension?
        if (in_array($entryInfo['extension'], $hideDir)) {
            // Skip it!
            continue;
        }            

        // Otherwise, just list it
        echo '<li>' . "$entry" . '</li>' . "
";
    }
}
closedir($handle);
echo '</ul>';

Notice that the extension does not contain the dot in front of it, so it should be:

$hideDir = array('php', 'html', 'css');