去命名参数

Question

How can I pass dictionary as list of arguments for function like in Python 3 in Go?

Python 3:

def bar(a,b,c):
    print(a,b,c)

args={c: 1, b: 2, a: 3}
bar(**args)

Go blank:

func bar( a, b, c int) {
    fmt.Printf("%d, %d, %d", a, b, c)
}

func main(){
    args := make(map[string]int)
    args["a"] = 3
    args["b"] = 2
    args["c"] = 1
    // what next ?
}

Answer 1

I don't believe this is possible. You'd need to use a struct to do anything even remotely close to this (and it is a remote likeness)

type Args struct {
    A, B, C int
}

func bar(args *Args) {
    fmt.Printf("%d, %d, %d", args.A, args.B, args.C)
}

func main() {
    args := new(Args)
    args.A = 3
    args.B = 2
    args.C = 1
    bar(args)
}