在Go中将CSV记录解组为struct

Question

The problem how to automatically deserialize/unmarshal record from CSV file into Go struct.

For example, I have

type Test struct {
  Name string
  Surname string
  Age int
}

And CSV file contains records

John;Smith;42
Piter;Abel;50

Is there an easy way to unmarshal those records into struct except by using "encoding/csv" package for reading record and then doing something like

record, _ := reader.Read()
test := Test{record[0],record[1],atoi(record[2])}

Answer 1

You could bake your own. Perhaps something like this:

package main

import (
    "fmt"
    "strconv"
    "strings"
)

type Test struct {
    Name    string
    Surname string
    Age     int
}

func (t Test) String() string {
    return fmt.Sprintf("%s;%s;%d", t.Name, t.Surname, t.Age)
}

func (t *Test) Parse(in string) {
    tmp := strings.Split(in, ";")
    t.Name = tmp[0]
    t.Surname = tmp[1]
    t.Age, _ = strconv.Atoi(tmp[2])
}

func main() {

    john := Test{"John", "Smith", 42}
    fmt.Printf("john:%v
", john)

    johnString := john.String()
    fmt.Printf("johnString:%s
", johnString)

    var rebornJohn Test
    rebornJohn.Parse(johnString)
    fmt.Printf("rebornJohn:%v
", rebornJohn)

}