http Request.FormFile：处理zip文件？

Question

I'm writing a web server in go.

On one of the pages, the user can upload a file.

I would like to be able to handle zip files.

In the archive/zip package, I only see two functions which allow me to read from a zip archive :

1. func OpenReader(name string) (*ReadCloser, error)
2. func NewReader(r io.ReaderAt, size int64) (*Reader, error)

I would like to avoid writing and reading back from the disk,
if I want to use the second function, I need to know the size of the uploaded file before calling the function.

Question

I will split my question in two parts :

1. What would be the idiomatic way to read the unzipped content of a zip file uploaded through a standard multipart/form-data html form ?

2. How can I get the actual size of a file uploaded through a html form ?

   func(req *http.Request) {
       f, h, err := req.FormFile("fileTag")
       if err != nil {
            panic(err)
       }
       var fileSize int = ??
   
       unzipper, err := zip.NewReader(f, fileSize)
   }
   

Answer 1

Here is a way I found to get the size :

func(req *http.Request) {
    f, h, err := req.FormFile("fileTag")
    if err != nil {
         panic(err)
    }
    fileSize, err := f.Seek(0, 2) //2 = from end
    if err != nil {
         panic(err)
    }
    _, err = f.Seek(0, 0)
    if err != nil {
         panic(err)
    }

    unzipper, err := zip.NewReader(f, fileSize)
}

I don't find this solution very elegant or idiomatic.

Isn't there some cleaner way to handle this case ?