Golang自定义排序比本地排序更快

Question

I was just playing around with sorting in golang and I found a qsort function on stackoverflow. It seems to run about twice as fast as the native sort function in golang. I've tried it with different input sizes and tested that it works.

Could anyone explain why this happens?

Here is the code you can test it on your pc:

package main

import (
    "fmt"
    "math/rand"
    "sort"
    "time"
)

func qsort(a []int) []int {
    if len(a) < 2 {
        return a
    }

    left, right := 0, len(a)-1

    // Pick a pivot
    pivotIndex := rand.Int() % len(a)

    // Move the pivot to the right
    a[pivotIndex], a[right] = a[right], a[pivotIndex]

    // Pile elements smaller than the pivot on the left
    for i := range a {
        if a[i] < a[right] {
            a[i], a[left] = a[left], a[i]
            left++
        }
    }

    // Place the pivot after the last smaller element
    a[left], a[right] = a[right], a[left]

    // Go down the rabbit hole
    qsort(a[:left])
    qsort(a[left+1:])

    return a
}

func main() {
    // Create an array with random integers
    rand.Seed(30)
    size := 1000000
    array1 := make([]int, size)
    start := time.Now()

    for i, _ := range array1 {
        array1[i] = rand.Int()
    }

    fmt.Println("Creating array with ", size, " elements...")
    fmt.Println("--- ", time.Since(start), " ---")
    // Create a copy of the unsorted array
    array2 := make([]int, size)
    copy(array2, array1)

    // Short using native function
    start = time.Now()
    sort.Ints(array1)

    fmt.Println("Sorting with the native sort...")
    fmt.Println("--- ", time.Since(start), " ---")

    // Sort using custom qsort
    start = time.Now()
    qsort(array2)

    fmt.Println("Sorting with custom qsort...")
    fmt.Println("--- ", time.Since(start), " ---")

}

Answer 1

The difference seems to largely be due to the fact that your Quicksort uses builtins. It slices and uses len. Keep in mind that sort.Sort takes in a sort.Interface. So every time you call len it calls slice.Len and every time you do array[i],array[j] = array[j],array[i] it has to call Swap(i,j).

I wrote a comparable version that works on an arbitrary qsort.Interface:

func Qsort(a Interface, prng *rand.Rand) Interface {
    if a.Len() < 2 {
        return a
    }

    left, right := 0, a.Len()-1

    // Pick a pivot
    pivotIndex := prng.Int() % a.Len()
    // Move the pivot to the right
    a.Swap(pivotIndex, right)

    // Pile elements smaller than the pivot on the left
    for i := 0; i < a.Len(); i++ {
        if a.Less(i, right) {

            a.Swap(i, left)
            left++
        }
    }

    // Place the pivot after the last smaller element
    a.Swap(left, right)

    // Go down the rabbit hole
    leftSide, rightSide := a.Partition(left)
    Qsort(leftSide, prng)
    Qsort(rightSide, prng)

    return a
}

Then I used Go's benchmark functionality (which you should always use for Benchmarks where possible).

For reference and transparency, qsort.Interface is defined as:

type Interface interface {
    sort.Interface
    // Partition returns slice[:i] and slice[i+1:]
    // These should references the original memory
    // since this does an in-place sort
    Partition(i int) (left Interface, right Interface)
}

The actual IntSlice implementation for qsort is:

type IntSlice []int

func (is IntSlice) Less(i, j int) bool {
    return is[i] < is[j]
}

func (is IntSlice) Swap(i, j int) {
    is[i], is[j] = is[j], is[i]
}

func (is IntSlice) Len() int {
    return len(is)
}

func (is IntSlice) Partition(i int) (left Interface, right Interface) {
    return IntSlice(is[:i]), IntSlice(is[i+1:])
}

Finally, here's the qsort_test.go file:

package qsort_test

import (
    "math/rand"
    "qsort"
    "sort"
    "testing"
    "time"
)

const size int = 1000000

var list = make([]int, size)
var prng = rand.New(rand.NewSource(int64(time.Now().Nanosecond())))

func BenchmarkQsort(b *testing.B) {
    for n := 0; n < b.N; n++ {
        b.StopTimer()
        for i := range list {
            list[i] = prng.Int()
        }
        b.StartTimer()

        qsort.Qsort(qsort.IntSlice(list), prng)
    }
}

func BenchmarkNativeQsort(b *testing.B) {
    for n := 0; n < b.N; n++ {
        b.StopTimer()
        for i := range list {
            list[i] = prng.Int()
        }
        b.StartTimer()

        qsort.NativeQsort(list, prng)
    }
}

func BenchmarkSort(b *testing.B) {
    for n := 0; n < b.N; n++ {
        b.StopTimer()
        for i := range list {
            list[i] = prng.Int()
        }
        b.StartTimer()

        sort.Sort(sort.IntSlice(list))
    }
}

The results (formatting mine):

PASS

BenchmarkQsort             5     513629360 ns/op
BenchmarkNativeQsort       10    160609180 ns/op
BenchmarkSort              5     292416760 ns/op

As you can see, the standard library's sort massively outperforms your qsort on average with random data. NativeQsort refers to the qsort functions you posted in your actual question, and it outperforms both. The only thing that's changed between that and Qsort is that I swapped the builtin functions for qsort.Interface. It follows, then, that genericity is likely the reason one is slower than the other.

Edit: There aren't many samples because of how expensive sorting is, so here are the results with -benchtime 10s just for slightly more representative results.

BenchmarkQsort                50     524389994 ns/op
BenchmarkNativeQsort         100     161199217 ns/op
BenchmarkSort                 50     302037284 ns/op