golang从函数返回对象

Question

I am struggling to understand exactly what is happening when you return a new object from a function in go.

I have this

func createPointerToInt() *int {
    i := new(int)
    fmt.Println(&i);
    return i;
}

func main() {
    i := createPointerToInt();
    fmt.Println(&i);
}

The values printed returned are

0x1040a128
0x1040a120

I would expect these two values to be the same. I do not understand why there is an 8 byte difference.

In what I see as the equivalent C code:

int* createPointerToInt() {
    int* i = new int;
    printf("%#08x
", i);
    return i;
}

int main() {
    int* r = createPointerToInt();
    printf("%#08x
", r);
    return 0;
}

The address returned is the same:

0x8218008
0x8218008

Am I missing something blindingly obvious here? Any clarification would be greatly appreciated!

Answer 1

You are printing the address of the pointer here fmt.Println(&i);. Try this:

func main() {
    i := createPointerToInt();
    fmt.Println(i); //--> Remove the ampersand
}

i is the pointer returned from createPointerToInt - while &i is the address of the pointer you are trying to print. Note in your C sample you are printing it correctly:

printf("%#08x
", r);
                 ^No ampersand here