dsv768456 2014-07-11 18:12
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I'm trying to pass the results of munging a slice into a channel. Here's the obviously broken version. I've tried a few ways of doing it that don't seem to work well. I'm looking for an idiomatic way of tackling this.

func gen() <-chan []int {
    c := make(chan []int)

    go func(c chan []int) {
        defer close(c)
        s := []int{0, 1, 2, 3}

        for i := 0; i < len(s); i++ {
            s[i] = -1
            c <- s
        }
    }(c)

    return c

}

func main() {
    for s := range gen() {
        fmt.Println(s)
    }
}

Result:

[-1 -1 2 3]
[-1 -1 2 3]
[-1 -1 -1 -1]
[-1 -1 -1 -1]
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1条回答 默认 最新

  • dtw52353 2014-07-11 18:21
    关注

    It does not work because the underlying array is the same. So you are modifying the same memory.

    Here is a working example. Copy the memory at each round.

    http://play.golang.org/p/OXfKVg8ZlZ

    package main
    
    import "fmt"
    
    func gen() <-chan []int {
        c := make(chan []int)
    
        go func(c chan []int) {
            defer close(c)
    
            s := []int{0, 1, 2, 3}
            for i := 0; i < len(s); i++ {
                s[i] = -1
                newSlice := make([]int, len(s))
                copy(newSlice, s)
                c <- newSlice
            }
        }(c)
    
        return c
    
    }
    
    func main() {
        for s := range gen() {
            fmt.Println(s)
        }
    }
    

    Output

    [-1 1 2 3]
    [-1 -1 2 3]
    [-1 -1 -1 3]
    [-1 -1 -1 -1]
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

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