doujiebo9849
doujiebo9849
2016-06-04 08:45
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使用time.Unix()从float解析十进制的unix时间戳?

This is pretty straightforward, but I couldn't find a response and figured that others might have the same question.

I have a Unix timestamp as a float, that includes a decimal value for fractions of seconds. What's the conversion factor to pass this float as two separate integers to the time package's time.Unix(sec int64, nsec int64) function, without losing the decimal precision?

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1条回答 默认 最新

  • doumi5223
    doumi5223 2016-06-04 08:48
    已采纳
    sec, dec := math.Modf(timeFloat);
    time.Unix(int64(sec), int64(dec*(1e9)));
    
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