使用time.Unix（）从float解析十进制的unix时间戳？

Question

This is pretty straightforward, but I couldn't find a response and figured that others might have the same question.

I have a Unix timestamp as a float, that includes a decimal value for fractions of seconds. What's the conversion factor to pass this float as two separate integers to the time package's time.Unix(sec int64, nsec int64) function, without losing the decimal precision?

Answer 1

sec, dec := math.Modf(timeFloat);
time.Unix(int64(sec), int64(dec*(1e9)));