douyangcheng4965 2017-07-13 15:07
浏览 33
已采纳

在Go中无法读取大于1024个字符的输入

I am using fmt.Scanf to read a string input in Golang. But the command stalls when we pass in a large input (>1024 characters). I am using Go version go1.8.3 darwin/amd64.

Here is the code

package main

import "fmt"

func main() {
    var s string
    fmt.Scanf("%s", &s)
    fmt.Println(s)
}

Here is the payload that fails https://pastebin.com/raw/fJ4QAZUZ

Go seems to take input till Jy in that payload which marks 1024 number of characters. So is 1024 a limit or what?

PS - I had already tampered the encoded cookie at that link, so no worries.

  • 写回答

1条回答 默认 最新

  • dqqyp90576 2017-07-13 15:19
    关注

    It's not the limit of the fmt package or fmt.Scanf(), this example properly scans more than 3KB:

    // src is a looooong text (>3KB)
    
    var s string
    fmt.Println(len(src))
    fmt.Sscanf(src, "%s", &s)
    fmt.Println(len(s))
    

    Try it on the Go Playground

    It's most likely the limit of your terminal. I also tried your unmodified version, pasted more than 10KB of text, and the result was 4096 bytes (Ubuntu linux 16.04, Bash).

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

报告相同问题?

悬赏问题

  • ¥15 关于#python#的问题:求帮写python代码
  • ¥20 MATLAB画图图形出现上下震荡的线条
  • ¥15 LiBeAs的带隙等于0.997eV,计算阴离子的N和P
  • ¥15 关于#windows#的问题:怎么用WIN 11系统的电脑 克隆WIN NT3.51-4.0系统的硬盘
  • ¥15 来真人,不要ai!matlab有关常微分方程的问题求解决,
  • ¥15 perl MISA分析p3_in脚本出错
  • ¥15 k8s部署jupyterlab,jupyterlab保存不了文件
  • ¥15 ubuntu虚拟机打包apk错误
  • ¥199 rust编程架构设计的方案 有偿
  • ¥15 回答4f系统的像差计算