Golang匿名结构初始化指针切片

Question

From Chapter 7 of GOPL (Section 7.6), I noticed this line:

var tracks = []*Track{
     {"Go", "Delilah", "From the Roots Up", 2012, length("3m38s")},
     {"Go", "Moby", "Moby", 1992, length("3m37s")},
     {"Go Ahead", "Alicia Keys", "As I Am", 2007, length("4m36s")},
     {"Ready 2 Go", "Martin Solveig", "Smash", 2011, length("4m24s")},
}

I was kind of confused by how it initialized the slice of Track pointers. So later I tried the following example:

type Ex struct {
    A, B int
}

a := []Ex{Ex{1, 2}, Ex{3, 4}}
b := []Ex{{1, 2}, {3, 4}}
c := []*Ex{&Ex{1, 2}, &Ex{3, 4}}
d := []*Ex{{1, 2}, {3, 4}}
e := []*Ex{{1, 2}, &Ex{3, 4}}

I found all of the 5 cases are okay with no errors. The {1, 2} seems to be a structure called "anonymous struct", but it confuses me since it works fine even when I am trying to fill in *Ex pointers instead of Ex struct.

Furthermore, when I try the following code, it complains syntax error:

f := []*Ex{&{1, 2}, &{3, 4}} // Syntax Error!

Can somebody help explain what is actually going on in these cases?

Answer 1

Please give more detail on your structure definition of Ex.

But, if Ex is implemented as this:

type Ex struct {
    t interface{}
    o interface{}
}

you don't give a pointer of anonymous struct because, the definition it's not know.

Also you can't do:

variable := new({1, 2})
// or
variable := {1, 2}

When you do:

b := []Ex{{1, 2}, {3, 4}}
// you create slice of Ex with two Ex struct
// so b := []Ex{Ex{t:1,o:2}, Ex{t:3, o:4}}

contrariwise:

f := []*Ex{&{1, 2}, &{3, 4}}
// you create slice of unknow definition type
// f = []Ex{Ex{t: addressOfUnknowType, o: addressOfUnknowType}}

I hope help you