douran9707
2019-01-23 02:50 阅读 260
已采纳

Golang指针值比较

I’m trying to figure out why this works.

I have an Item struct

type item struct {
    name string
    someOtherValue int 
}

and another struct

type someStruct struct {
    items []item
}

I have a function where I want to loop through and update the values.

func (s someStruct) update() {
    for i := range s.items {
         item := &s.items[i]

        if item.name == “Something” {
            doSomething(item)
        }
    }
}

When I pass item to the doSomething function, it will update the item at that address (works as planned).

My question is, why does item.name work if item supposed to be an address?

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1条回答 默认 最新

  • 已采纳
    doushu5805 doushu5805 2019-01-23 03:36

    Because Golang has automatically dereferenced pointers.

    item.name is converted to (*item).name

    As with selectors, a reference to a non-interface method with a value receiver using a pointer will automatically dereference that pointer: pt.Mv is equivalent to (*pt).Mv.

    You can read all the rules in Selectors specification

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