doukong1391 2014-07-16 14:28
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在go中列出和访问目录

i need some help in golan to write a program that can search through a given directory and its subdirectories to look for a particular word word in each of them.

this what i have so far to list the directories and save them as an array. now i want to check each of them to see if it has children, if yes, i should open it until i reach the last level of the tree.

package main

import (
    "fmt"
    "os"


)

func main() {

    d, err := os.Open("/Perkins")
   // fmt.Println(d.Readdirnames(-1))

    y, err:=d.Readdirnames(-1) // 
    fmt.Println(y)
    for i:=0; i<len(y); i++{
        if y[i]!=" "{
            Folders:=y[i]
            temp,err:=os.Open("/"Folders) //how do i out the array element as a path?
            fmt.Println (temp)

            fmt.Println(err)
            }
    }
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  • douhu5837 2014-07-16 15:00
    关注

    Note: "/"Folders wouldn't work: "/" + Folders

    In your case, this should work better:

    temp,err:=os.Open("/Perkins/" + Folders)
    

    (even though 'Folders' is not a good name, 'subfolder' would be more appropriate)


    A more efficient way, as commented by chendesheng (see answer), would be (as in this class) to use path/filepath/#Walk:

    package main
    
    import (
      "fmt"
      "os"
      "path/filepath"
    )
    
    func main() {
      filepath.Walk("/Perkins", func(path string, info os.FileInfo, err error) error {
        fmt.Println(path)
        return nil
      })
    }
    

    That will list all the file, but you can associate it with a function which will filter those: see this example:

    matched, err := filepath.Match("*.mp3", fi.Name())
    

    You can then ignore the files you don't want and proceed only for the ones matching your pattern.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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