Go中无符号整数的二进制表示形式

Question

Is there a built-in function to convert a uint to a slice of binary integers {0,1} ?

>> convert_to_binary(2)
[1, 0]

Answer 1

I am not aware of such a function, however you can use strconv.FormatUint for that purpose.

Example (on play):

func Bits(i uint64) []byte {
    bits := []byte{}

    for _, b := range strconv.FormatUint(i, 2) {
         bits = append(bits, byte(b - rune('0')))
    }

    return bits
}

FormatUint will return the string representation of the given uint to a base, in this case 2, so we're encoding it in binary. So the returned string for i=2 looks like this: "10". In bytes this is [49 48] as 1 is 49 and 0 is 48 in ASCII and Unicode. So we just need to iterate over the string, subtracting 48 from each rune (unicode character) and converting it to a byte.