douang2297 2019-08-28 05:39
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反射性设置作为接口{}传递的结构的字段

The following works fine:

type MyStruct struct {
    MyField int32
}

func SetReflectConcrete(obj *MyStruct, fieldName string, newValue interface{}) {
    objElem := reflect.ValueOf(obj).Elem()
    field := objElem.FieldByName(fieldName)
    field.Set(reflect.ValueOf(newValue))
}

func main() {
    myStruct := MyStruct{123}
    SetReflectConcrete(myStruct, "MyField", int32{1234})
}

How can I make a variant of the SetReflect function that works on any struct? All my attempts so far have failed. The signature would be something like this:

func SetReflectInterface(obj interface{}, fieldName string, newValue interface{})

And is this even possible, when calling it like

SetReflectInterface(myStruct, "MyField", int32{1234})

or would it have to be called like

SetReflectInterface(&myStruct, "MyField", int32{1234})

(After all, interface{} has a pointer to the struct.)

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1条回答 默认 最新

  • doqw89029 2019-08-28 05:42
    关注

    Declare the argument as type interface{} as you noted. Pass a pointer to the struct as in the last code snippet.

    func SetReflectConcrete(obj interface{}, fieldName string, newValue interface{}) {
        objElem := reflect.ValueOf(obj).Elem()
        field := objElem.FieldByName(fieldName)
        field.Set(reflect.ValueOf(newValue))
    }
    
    myStruct := MyStruct{123}
    SetReflectConcrete(&myStruct, "MyField", int32(1234))
    

    Run it on the playground.

    The reflect value must be addressable to set a field. The value will not be addressable if created directly from a struct.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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