切片迭代顺序

Question

Ok, i think this may be an old question, but i didn't find anything over the stackoverflow. In go , the iteration order over a map is not guranteed to be reproducible. So, the way suggest is to hold the keys in a slice and sort that slice. Then iterate over that slice to retrieve the values from the map, so that we get them in order(since slice composed of keys is sorted, so will be in reproducible order). So this goes to imply that the slice need be sorted else iteration over the slice will also not give reproducible order. But when i tried the below code in playground, i always found the order maintained in iteration, then in the map iteration case, why the slice of keys need to be sorted?

func main() {
    var mySlice = make([]string, 0)
    mySlice = append(mySlice, "abcd")
    mySlice = append(mySlice, "efgh")
    mySlice = append(mySlice, "ijkl")
    mySlice = append(mySlice, "mnop")
    mySlice = append(mySlice, "qrst")
    mySlice = append(mySlice, "uvwxyz")
    for _, val := range mySlice {
        fmt.Println(val)
    }
    fmt.Println(strings.Join(mySlice, "|"))

}

Output:

abcd
efgh
ijkl
mnop
qrst
uvwxyz
abcd|efgh|ijkl|mnop|qrst|uvwxyz

Answer 1

The only reason your slice is sorted is because you're appending items in already sorted order. If you appended items in an unsorted order like this

var mySlice = make([]string, 0)
mySlice = append(mySlice, "mnop")
mySlice = append(mySlice, "efgh")
mySlice = append(mySlice, "uvwxyz")
mySlice = append(mySlice, "ijkl")
mySlice = append(mySlice, "abcd")
mySlice = append(mySlice, "qrst")

(or populated a slice by pulling keys from a map, which would be unsorted), then the order on iteration would be unsorted (consistent, yes, but consistently unsorted). So, if your objective is to use the slice to pull items from a map in sorted order, then you need to first sort the slice, unless you can guarantee the slice items were inserted in an already sorted order.