dtjpnd7517 2018-08-03 09:28
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filepath.Join删除点

i have a problem with create path for rsync.

x := filepath.Join("home", "my_name", "need_folder", ".")
fmt.Println(x)

I get "home/my_name/need_folder", but need "home/my_name/need_folder/.", how fix without concat? In linux folder with name "." not impossible.

Thank you!

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  • dthp96899 2018-08-03 10:21
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    You can't do that with the filepath.Join() as its documentation states:

    Join calls Clean on the result...

    And since . denotes the "current" directory, it will be removed by filepath.Clean():

    It applies the following rules iteratively until no further processing can be done:

    1. [...]

    2. Eliminate each . path name element (the current directory).

    And in fact you can't do what you want with the path/filepath package at all, there is no support for this operation.

    You need to use string concatenation manually. Use filepath.Separator for it, it'll be safe:

    x := filepath.Join("home", "my_name", "need_folder") +
        string(filepath.Separator) + "."
    fmt.Println(x)
    

    Output (try it on the Go Playground):

    home/my_name/need_folder/.
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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