dongzhuonao8429 2015-02-05 18:11
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大猩猩Mux用于子路径路由

I have the following routes:

router.Methods("POST").Path("/my_post_01").HandlerFunc(myHandler1)
router.Methods("GET").Path("/my_get_01").HandlerFunc(myHandler2)

router.Methods("POST").Path("/my_post_02").HandlerFunc(myHandler3)
router.Methods("GET").Path("/my_get_02").HandlerFunc(myHandler4)

router.Methods("POST").Path("/my_post_03").HandlerFunc(myHandler5)
router.Methods("GET").Path("/my_get_03").HandlerFunc(myHandler6)

router.Methods("POST").Path("/my_post_04").HandlerFunc(myHandler7)
router.Methods("GET").Path("/my_get_04").HandlerFunc(myHandler8)

router.Methods("POST").Path("/my_post_05").HandlerFunc(myHandler9)
router.Methods("GET").Path("/my_get_05").HandlerFunc(myHandler10)

As I have more and more routes, it gets harder to manage.

I want to do something like:

router.Path("/my/*").HandleFunc(mypackage.RegisterHandler)

with all handlers being separated in another package

Is there any way that I can match those paths in a separate package?

Thanks,

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  • dongqiong8021 2015-02-05 21:36
    关注

    You could create a package for your router then import said package and add your routes.

    Router

    package router
    
    var Router = mux.NewRouter()
    // handle "/my/" routes
    var MyRouter = Router.PathPrefix("/my").Subrouter()
    

    another package

    import "/path/to/router"
    
    func init() {
        router.MyRouter.Methods("POST").Path("/post_01").HandlerFunc(myHandler1)
    }
    

    In main

    import "/path/to/router"
    
    func main() {
        http.Handle("/", router.Router)
    
        //...
    }
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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