dongqiuqiu4736 2018-10-27 16:39
浏览 121
已采纳

fmt.Println()函数中的异常输出

I'm starting with golang (total noob), and I'm using a simple wrapper function for fmt.Println(str), just because it's shorter and I'm more used to it:

func echo(str ...interface{}) {
  fmt.Println(str)
}

The thing is that the output for echo("Hello") is [Hello] instead of Hello.

Am I missing some syntax detail here? How can I change the function to work as expected?

Besides the actual need for this function, I'm interested in the language-specific details about this issue.

Thanks!

  • 写回答

1条回答 默认 最新

  • doulangbi6869 2018-10-27 16:43
    关注

    The problem is that you send to fmt.Println parameter as a slice, but not as varadic.

    Change your method to :

    func echo(str ...interface{}) {
        fmt.Println(str...)
    }
    

    And it will work as you expect.

    Check topic Arguments to variadic functions from this site.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

报告相同问题?

悬赏问题

  • ¥15 metadata提取的PDF元数据,如何转换为一个Excel
  • ¥15 关于arduino编程toCharArray()函数的使用
  • ¥100 vc++混合CEF采用CLR方式编译报错
  • ¥15 coze 的插件输入飞书多维表格 app_token 后一直显示错误,如何解决?
  • ¥15 vite+vue3+plyr播放本地public文件夹下视频无法加载
  • ¥15 c#逐行读取txt文本,但是每一行里面数据之间空格数量不同
  • ¥50 如何openEuler 22.03上安装配置drbd
  • ¥20 ING91680C BLE5.3 芯片怎么实现串口收发数据
  • ¥15 无线连接树莓派,无法执行update,如何解决?(相关搜索:软件下载)
  • ¥15 Windows11, backspace, enter, space键失灵