dongqiuqiu4736 2018-10-27 16:39
浏览 121
已采纳

fmt.Println()函数中的异常输出

I'm starting with golang (total noob), and I'm using a simple wrapper function for fmt.Println(str), just because it's shorter and I'm more used to it:

func echo(str ...interface{}) {
  fmt.Println(str)
}

The thing is that the output for echo("Hello") is [Hello] instead of Hello.

Am I missing some syntax detail here? How can I change the function to work as expected?

Besides the actual need for this function, I'm interested in the language-specific details about this issue.

Thanks!

  • 写回答

1条回答 默认 最新

  • doulangbi6869 2018-10-27 16:43
    关注

    The problem is that you send to fmt.Println parameter as a slice, but not as varadic.

    Change your method to :

    func echo(str ...interface{}) {
        fmt.Println(str...)
    }
    

    And it will work as you expect.

    Check topic Arguments to variadic functions from this site.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

报告相同问题?

悬赏问题

  • ¥15 计组这些题应该咋做呀
  • ¥60 更换迈创SOL6M4AE卡的时候,驱动要重新装才能使用,怎么解决?
  • ¥15 让node服务器有自动加载文件的功能
  • ¥15 jmeter脚本回放有的是对的有的是错的
  • ¥15 r语言蛋白组学相关问题
  • ¥15 Python时间序列如何拟合疏系数模型
  • ¥15 求学软件的前人们指明方向🥺
  • ¥50 如何增强飞上天的树莓派的热点信号强度,以使得笔记本可以在地面实现远程桌面连接
  • ¥20 双层网络上信息-疾病传播
  • ¥50 paddlepaddle pinn