正则表达式查找字符串中的3位整数

Question

I have a DNS query that is returning the fields I need, but now I need to parse a 3 digit number from the response.

The reponse block I am parsing looks like this:

_ref: "network/ZG5zLm5ldHdvcmskMTAuMC45MS4wLzI0LzA:10.0.91.0/24/default"

comment: "Vlan xyz site number 777 "

network: "10.0.91.0/24"

network_view: "default"

This looked like the right regexp, but I'm not getting a response:

re := regexp.MustCompile("[0-9]+")
fmt.Println(re.FindAllString("%s", -1))

Answer 1

Check the documentation for regexp.FindString(string) to make sure you've got the arguments right; you should be giving it the search string...

re := regexp.MustCompile(`\d{3}`)
search := "Vlan xyz site number 777 "
match := re.FindString(search)
fmt.Printf("OK: %q
", match)
// OK: "777"