2015-06-02 06:08
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I'm lazy, want to pass many variables to Printf function, is it possible? (The sample code is simplified as 3 parameters, I require more than 10 parameters).

I got the following message:

cannot use v (type []string) as type []interface {} in argument to fmt.Printf

s := []string{"a", "b", "c", "d"}  // Result from regexp.FindStringSubmatch()
fmt.Printf("%5s %4s %3s
", s[1], s[2], s[3])  

v := s[1:]
fmt.Printf("%5s %4s %3s
", v...)  

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我很懒,想将许多变量传递给 Printf 函数,是否有可能 ? (示例代码简化为3个参数,我需要10个以上的参数)。


\ n


  s的参数中不能使用v(类型[]字符串)作为类型[] interface {}  ] string {“ a”,“ b”,“ c”,“ d”} // regexp.FindStringSubmatch()
”,s [1],s的结果 [2],s [3])
v:= s [1:] 
”,v ...)
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1条回答 默认 最新

  • duancao2082 2015-06-02 06:15

    Yes, it is possible, just declare your slice to be of type []interface{} because that's what Printf() expects. Printf() signature:

    func Printf(format string, a ...interface{}) (n int, err error)

    So this will work:

    s := []interface{}{"a", "b", "c", "d"}
    fmt.Printf("%5s %4s %3s
    ", s[1], s[2], s[3])
    v := s[1:]
    fmt.Printf("%5s %4s %3s
    ", v...)

    Output (Go Playground):

    b    c   d
    b    c   d

    []interface{} and []string are not convertible. See this question+answers for more details:

    Type converting slices of interfaces in go

    If you already have a []string or you use a function which returns a []string, you have to manually convert it to []interface{}, like this:

    ss := []string{"a", "b", "c"}
    is := make([]interface{}, len(ss))
    for i, v := range ss {
        is[i] = v
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