在golang中，如何覆盖嵌入式结构的方法

Question

Code here

package main

import "fmt"

func main() {
    t16()
}

type Base struct {
    val int
}
func (b *Base)Set(i int) {
    b.val = i
}
type Sub struct {
    Base
    changed bool
}

func (b *Sub)Set(i int) {
    b.val = i
    b.changed = true
}
func t16() {
    s := &Sub{}
    s.Base.Set(1)
    var b *Base = &s.Base
    fmt.Printf("%+v
", b)
    fmt.Printf("%+v
", s)
}

I want to make Sub act as Base, but when I call Set, for Sub it will mark the changed.I know there is no polymorphism or proxy in golang, but is there any way to do this, and not effect the Base?

UPDATED

I hope when I call Base.Set it will mark the change, for user, they don't know they actually use the Sub, so I can monitor the Base behave.

func t16() {
    s := &Sub{}
    var b *Base = &s.Base
    b.Set(10)
    fmt.Printf("%+v
", b)
    fmt.Printf("%+v
", s)
}

Answer 1

I think I should use the interface here, it achieve what I want, but affected the base

func main() {
    t16()
}

type Base interface {
    Set(int)
}
type base struct {
    val int
}
func (b *base)Set(i int) {
    b.val = i
}
type Sub struct {
    base
    changed bool
}

func (b *Sub)Set(i int) {
    b.val = i
    b.changed = true
}
func t16() {
    s := &Sub{}
    s.Set(1)
    var b Base = s
    fmt.Printf("%+v
", b)
    fmt.Printf("%+v
", s)
}