dsue14118 2016-12-03 17:01
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I'm testing out how to unmarshal a json response from an API I'm using.

The json looks something like the following;

body := []byte(`[
    {"name":"Name1", "value":100.00},
    {"name":"Name2", "value":200.00}

I've searched around for various ways to do this, but fail to get this to work. The unmarshal returns zero values. I also get an error "unexpected end of JSON input" (I've removed the error handling in the example).

Full code example - https://play.golang.org/p/VMdWuAm6HS


  1. https://godoc.org/encoding/json#RawMessage
  2. Golang json Unmarshal "unexpected end of JSON input"
  3. How to unmarshal json into interface{} in golang?
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  • drbae3964 2016-12-03 17:17

    Your input JSON can be modeled with a simple []Obj where Obj is your type:

    type Obj struct {
        Name  string  `json:"name"`
        Value float32 `json:"value"`

    Nothing else is required, really:

    body := []byte(`[
        {"name":"Name1", "value":100.00},
        {"name":"Name2", "value":200.00}]`)
    var res []Obj
    err := json.Unmarshal(body, &res)
    ", res, err)

    Output contains the data from the input JSON (try it on the Go Playground):

    []main.Obj{main.Obj{Name:"Name1", Value:100}, main.Obj{Name:"Name2", Value:200}}

    Back to your code:

    Where you're going wrong is that you use this model:

    type Obj struct {
        Name string `json:"name"`
        Value float32 `json:"value"`
    type Result struct {
        Data json.RawMessage
    var res []Result

    But this res variable would model the following JSON:

        {"Data":{"name":"Name1", "value":100.00}},
        {"Data":{"name":"Name2", "value":200.00}}

    I think you can see the difference: the elements of the array here are JSON Objects with a "Data" field, which then are modeled with your Obj. This input JSON is then properly parsed with your original parsing code, you can try it on the Go Playground:

    [{{"name":"Name1", "value":100.00}} {{"name":"Name2", "value":200.00}}] 
    &main.Obj{Name:"Name1", Value:100} 
    &main.Obj{Name:"Name2", Value:200}
    本回答被题主选为最佳回答 , 对您是否有帮助呢?



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