golang time.Now（）.Unix（）文档与实现之间的差异？

Question

这个链接https://golang.org/pkg/time/#Unix介绍了func Unix(sec int64, nsec int64) Time函数的签名含义, 还会返回一个time对象。

但是下面的程序中止了错误消息：

14: cannot use now.Unix() (type int64) as type time.Time in assignment`

func main() {
    var now time.Time
    now = time.Now()
    fmt.Println(now)

    var secs time.Time
    secs = now.Unix()
    fmt.Println(secs)
}

以下版本的程序生成输出：

func main() {
    var now time.Time
    now = time.Now()
    fmt.Println(now)

    // var secs time.Time
    secs := now.Unix()
    fmt.Println(secs)
}

2016-04-12 18:20:22.566965512 -0400 EDT

1460499622

这仅仅是文档中的错误吗？

Answer 1

The docs are correct, you're looking at the wrong version of Unix. The method you're using is this; https://golang.org/pkg/time/#Time.Unix it takes no arguments, is called on a time object and returns the unix time as an int64. The version you're referencing takes two arguments, both int64's, the seconds and nanoseconds? (not positive that's what the nseconds stands for) which represent a time in unix format and it returns a time.Time

So to extend your second example;

func main() {
    var now time.Time
    now = time.Now()
    fmt.Println(now)

    // var secs time.Time
    secs := now.Unix()
    fmt.Println(secs)
    t := time.Unix(secs, 0) // get a time from the seconds value which is a unix time
    fmt.Println(t)
}

Here's the above in play with one other line added to print the type of secs. https://play.golang.org/p/KksPPbQ1Jy