使用Golang对文件名中的数字进行字符串排序

Question

I'm trying to convert some old python code into Go lang. But i got stuck at sorting the files in a folder. Since the files are always AMA1.txt, AMA2.txt etc. In python source code i did this:

files=[]
for file in os.listdir(someDir):

    if file.endswith(".txt"):
     files.append(file) 

convert = lambda text: int(text) if text.isdigit() else text 
alphanum_key = lambda key: [ convert(c) for c in re.split('([0-9]+)',key) ]

files.sort( key=alphanum_key )

for i in files:
    print (i)

I got so far, but missing the sorting :

func main() {
    dirname := "someDir"
    d, err := os.Open(dirname)

    if err != nil {
        fmt.Println(err)
    }

    defer d.Close()

    fi, err := d.Readdir(-1)

    if err != nil {
        fmt.Println(err)
    }

    for _, fi := range fi {
        if fi.Mode().IsRegular() {
            fmt.Println(fi.Name())
        }
    }
}

Answer 1

Collect each item into a slice and then use the sort package to sort them. There are examples and explanation in the package docs.

In your case it may be easier to extract the numbers prior to sorting. For that, you might find fmt.Sscanf useful.