在go lang中，为什么是7？ 断言（5 ^ 2 == 7）

Question

in go lang, why this is 7 ?

assert(5^2 == 7)

so strange. I tried to google it. but google does not work well with special characters. Thanks.

Answer 1

The ^ operator is the XOR (exclusive OR), applied bitwise if operands are numbers.

5 = 101b // in binary, but Go doesn't have binary literals
2 = 010b
XOR:
7 = 111b