如何将uint16序列转换为float32？

Question

I've a sequence [66 106 179 86](those numbers are two 16bit register in modbus) generated by modbus library(conversion code), now how can I convert this sequence in a 32 float number?

I've tried []uint32{66,106, 179, 86} as argument for Float32frombits but doesn't accept uint32 lists.

Answer 1

Using math.Float32fromBits()

We may use math.Float32fromBits() to obtain a float32 value from its "binary" representation. But in order to use it, we need the 4 bytes data packed into a uint32 value. For that, we may use binary.ByteOrder.Uint32():

data := []byte{66, 106, 179, 86}

bits := binary.BigEndian.Uint32(data)
f := math.Float32frombits(bits)
fmt.Println(f)

Output (try it on the Go Playground):

58.675133

This solution is faster if we just want to read a single float32 value.

Using binary.Read()

Another option would be to use binary.Read() to fill fixed-size values from an io.Reader. If we have our data as a byte slice, we can use bytes.NewBuffer() to obtain an io.Reader from it:

data := []byte{66, 106, 179, 86}
var f float32
err := binary.Read(bytes.NewBuffer(data), binary.BigEndian, &f)
fmt.Println(f, err)

Output (try it on the Go Playground):

58.675133 <nil>

This solution is preferred if we have to read a series of float32 values from the input.