Go会修复或共享C的危险隐式->无符号转换吗？

Question

In "21st Century C", Ben Klemens describes how C automatically converts signed numbers to unsigned, in comparison expressions for example. Does Go share this same hazardous behavior, or does Go approach it differently?

Answer 1

There are no implicit conversions in Go. In order to compare or do arithmetic with two values of different types, you must do manual and explicit type conversion.

a := 3          // numerical constant 3 defaults to int
b := uint(2)
c := a < b      // compiler error
d := a < int(b) // OK