dougou8552 2015-05-25 23:02
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Golang-将结构作为参数传递给函数

I have to parse some nested JSON, which translates into a Go type, like this:

type Config struct {
Mail           struct {
                   From     string
                   To       string
                   Password string
               }
Summary        struct {
                   Send     bool
                   Interval int
               }
}

Now I want to call a function for each key (Mail, Summary), I tried it like this: utils.StartNewMailer(config.Mail) The problem is, how do I construct the called function, I tried to mirror the Mail struct (and called it mailConfig), since I can't pass an arbitrary struct as an argument.
func StartNewMailer(conf mailConfig){ //..., but that doesn't work either, I get the following compiler error message: cannot use config.Mail (type struct { From string; To string; Password string }) as type utils.mailConfig in argument to utils.StartNewMailer
Do I have to pass in every single value to the called function or is there a nicer way to do this?

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  • duanli6834 2015-05-25 23:43
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    utils.mailConfig fields should be exported, as in the literal struct field in Config type.

    type mailConfig struct {
        From     string
        To       string
        Password string
    }
    

    I suggest declaring inner structs as types themselves instead of using struct literals.

    type Mail struct {
        From     string
        To       string
        Password string
    }
    
    type Summary struct {
        Send     bool
        Interval int
    }
    
    type Config struct {
        Mail
        Summary
    }
    
    func StartNewMailer(Mail mailConfig)
    
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