dongsha9208 2018-12-22 02:03
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Golang返回nil不返回nil

I created a custom error type to wrap errors around for easier debugging in Golang. It works when there are errors to print, but now it is causing a panic.

Demo

type Error struct {
    ErrString string
}

func (e *Error) Error() string {
    return e.ErrString
}

func Wrap(err error, str string) *Error {
    if err == nil {
        return nil
    }
    e := &Error{
        ErrString: str + err.Error(),
    }
    return e
}

When I call a function an it doesn't return an error, I should still be able to wrap the error.

The expected behavior is that if the error is nil, it should simply ignore it, unfortunately it does the opposite.

func foo() error {
    err := bar()
    return Wrap(err, "bar called")
}

func bar() error {
    return nil
}

func main() {
    err := foo()
    if err != nil {
        fmt.Printf("Found error %v
",err)
        return
    }
    fmt.Println("No Errors")
}

I expect it to print No errors. Instead it prints Found error <nil> even though the error is nil.

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3条回答 默认 最新

  • drbhjey445647 2018-12-22 02:26
    关注
    if err != nil
    

    Is comparing a the err variable to a nil error , but its actually a nil *Error

    Changing the code to

    err:=foo()
    var  nilerror *Error = nil
    if err != nilerror {
        fmt.Printf("Found error %v
    ",err)
        return
    }
    fmt.Println("No Errors")
    

    Yields the predicted result.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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