执行：Varint返回的值与读取的值不同

Question

Why does binary.Varint return different results than binary.Read?

package main

import "fmt"
import "encoding/binary"
import "bytes"

func main() {
    b := []byte{0x18, 0x2d, 0x44, 0x54, 0xfb, 0x21, 0x09, 0x40}
    var i1 int64

    buf := bytes.NewBuffer(b)
    binary.Read(buf, binary.LittleEndian, &i1)
    fmt.Printf("%s, %d
", i1, i1)

    i2, _ := binary.Varint(b)
    fmt.Printf("%s, %d
", i2, i2)
}

Returns:

%!s(int64=4614256656552045848), 4614256656552045848
%!s(int64=12), 12

Here's a link to the playground: https://play.golang.org/p/vlrl_CHq0v

Answer 1

Varint is a specific encoding, that means that the byte value it reads off the wire/from the file is not an actually integer value, but an encoding. Read on the other hand, just reads bytes in whichever byte order you passed to it.